3.5.7 \(\int \frac {x^2}{\sqrt {a+b x^3}} \, dx\) [407]

Optimal. Leaf size=18 \[ \frac {2 \sqrt {a+b x^3}}{3 b} \]

[Out]

2/3*(b*x^3+a)^(1/2)/b

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Rubi [A]
time = 0.00, antiderivative size = 18, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {267} \begin {gather*} \frac {2 \sqrt {a+b x^3}}{3 b} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^2/Sqrt[a + b*x^3],x]

[Out]

(2*Sqrt[a + b*x^3])/(3*b)

Rule 267

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a + b*x^n)^(p + 1)/(b*n*(p + 1)), x] /; FreeQ
[{a, b, m, n, p}, x] && EqQ[m, n - 1] && NeQ[p, -1]

Rubi steps

\begin {align*} \int \frac {x^2}{\sqrt {a+b x^3}} \, dx &=\frac {2 \sqrt {a+b x^3}}{3 b}\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 18, normalized size = 1.00 \begin {gather*} \frac {2 \sqrt {a+b x^3}}{3 b} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^2/Sqrt[a + b*x^3],x]

[Out]

(2*Sqrt[a + b*x^3])/(3*b)

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Maple [A]
time = 0.14, size = 15, normalized size = 0.83

method	result	size
gosper	\(\frac {2 \sqrt {b \,x^{3}+a}}{3 b}\)	\(15\)
derivativedivides	\(\frac {2 \sqrt {b \,x^{3}+a}}{3 b}\)	\(15\)
default	\(\frac {2 \sqrt {b \,x^{3}+a}}{3 b}\)	\(15\)
trager	\(\frac {2 \sqrt {b \,x^{3}+a}}{3 b}\)	\(15\)
risch	\(\frac {2 \sqrt {b \,x^{3}+a}}{3 b}\)	\(15\)
elliptic	\(\frac {2 \sqrt {b \,x^{3}+a}}{3 b}\)	\(15\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(b*x^3+a)^(1/2),x,method=_RETURNVERBOSE)

[Out]

2/3*(b*x^3+a)^(1/2)/b

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Maxima [A]
time = 0.29, size = 14, normalized size = 0.78 \begin {gather*} \frac {2 \, \sqrt {b x^{3} + a}}{3 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^3+a)^(1/2),x, algorithm="maxima")

[Out]

2/3*sqrt(b*x^3 + a)/b

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Fricas [A]
time = 0.34, size = 14, normalized size = 0.78 \begin {gather*} \frac {2 \, \sqrt {b x^{3} + a}}{3 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^3+a)^(1/2),x, algorithm="fricas")

[Out]

2/3*sqrt(b*x^3 + a)/b

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Sympy [A]
time = 0.19, size = 24, normalized size = 1.33 \begin {gather*} \begin {cases} \frac {2 \sqrt {a + b x^{3}}}{3 b} & \text {for}\: b \neq 0 \\\frac {x^{3}}{3 \sqrt {a}} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2/(b*x**3+a)**(1/2),x)

[Out]

Piecewise((2*sqrt(a + b*x**3)/(3*b), Ne(b, 0)), (x**3/(3*sqrt(a)), True))

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Giac [A]
time = 1.00, size = 14, normalized size = 0.78 \begin {gather*} \frac {2 \, \sqrt {b x^{3} + a}}{3 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^3+a)^(1/2),x, algorithm="giac")

[Out]

2/3*sqrt(b*x^3 + a)/b

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Mupad [B]
time = 1.10, size = 14, normalized size = 0.78 \begin {gather*} \frac {2\,\sqrt {b\,x^3+a}}{3\,b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(a + b*x^3)^(1/2),x)

[Out]

(2*(a + b*x^3)^(1/2))/(3*b)

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